Recent content by Anasazi

Hello Barry, Thanks very much for that. I have to admit though, I don't understand what's happening with the maths there, it seems you're calculating distance, velocity and acceleration. Nevertheless, I'm a little more interested in the writing there than the maths... My apologies, there...

Well, the crank has a maximum acceleration of around 128.015 metres per second and the weight is 2.1 KG, which gives a force of approx. 268 Newtons as per the first post by CWatters:

Hello, The 279 number is in the "Crank & Object Force Calculations" section, but here it is below: Total Force to move crank and object (Newtons) : (Friction force for movement + Force required for crank) Total Force to move crank and object (Newtons) : 10.29 + 268.8322325 Total Force to move...

Actually, I've been searching about and I wonder would I be better getting a moderator to move this thread to the "Mechanical Engineering" forum?

Hello there, Thanks for the prompt reply. So, am I going down the wrong route by using braking torques etc. and overcomplicating it? If so, where would these things fit in? Well, I know that I need to apply more than 10.29 Newtons of force to get the object to move due to the static friction...

Revised question. Hello! Thanks once again for the tips on things I’ve missed such as acceleration and friction. I’ve spent the past couple of days rooting round trying to find things out. I’ve posted below a revised question that should hopefully explain things a little better along with some...

Hi David. That's excellent - thank you very much for all your help and patience through this thread - it's greatly appreciated. Even though it was a straight forward case of putting values into a formula, I struggled quite a bit with this one. :) Many thanks once more to SteamKing as well.

Edit Very sorry - ignore this post.

Thank for clarifying that - well, it would seem that the formula is working, however from a practical point of view, it makes little sense. If you assume a crank as depicted from wiki: http://upload.wikimedia.org/wikipedia/commons/8/8b/Crank_mechanism_geometry_sk.png then why would the...

Hello davidchen, Thanks for taking the time to reply. Yes, that's correct and is what I'm looking for - my apologies, I messed up the title... Hm, well as you've noticed the formula gives the acceleration of the piston at a given crank angle. I'm not knowledgeable enough with maths to be...

Hello SammyS, Unfortunately, I cannot as this isn't homework, it's for a personal project I'm working on, and I'm afraid I'm not anything like a physics student so my knowledge may have some very large gaps in it. :) I've clarified the title and the wording in a couple of places. I'm after the...

Title: The title should actually read Finding the acceleration of a piston with respect to a cranks angle Homework Statement I have found a formula for calculating the acceleration of a piston, with respect to a cranks angle, however I've also found a couple of online calculators that give...

Well... After putting it like that, it makes my previous statement seem a little silly! :) Haha, thank you. I shall gather an appropriate friction coefficient. :)

Hello BarryJ, Ah, so friction has to come into it somehow then? I'll have a look for some sample friction coefficients... Thanks.

Hello there CWatters, Thanks for taking the time to reply. My apologies, I hadn't realized the direction was needed as I assumed that the difference between the two over such a small distance would be negligible. Although to answer your question, the box is moving horizontally. Ah okay. So if...