Recent content by andorei

@zj8651731 - Does this mean that the question itself is wrong?

*Also assuming that the 2seconds is the time it took for the stone to fall to the bottom of the pit.

Only the time is known. But using (at^2)/2, the answer is reasonable.

Homework Statement A boy dropped a stone at a pit. A sound was heard 2 seconds later. What is the distance of the bottom of the pit? The Attempt at a Solution Given: Time - 2 Seconds Vsound - 332m/s 332m/s * 2s = 664meters. I think it is somewhat wrong. Maybe purely wrong. I...

Multiply N by the area which cancels out both m^2 which then yields 7.84N as a result. Thank you so much TaxOnFear and LawrenceC. I have to sleep now, it's late night here in the Philippines. Thanks again.

The choices that are given in the book is 7.38N 7.62N 7.75N 7.84N

I'm totally aware of that. But I was only at the first two. With multiplying with the height the answer would be "7840N/m^2"

How can that be, sir? Density * Gravity = 1.0x103kg/m3(9.81m/s2) = 9800N/m3 What made the cubic meter turn to a meter squared?

9800N/m^3 then what?

density, gravity and height? Coz' height cancels out the m^3? Sorry for messing things up.

Wait I found another formula, I think this one could be possible for solving the unknown. F=(density)(Area)(Height)(Gravity)

By multiplying Area and Pressure.

Hmm.. Formula for Pressure P=F/A , or Pascal's principle?

Okayy fine. I get lost on what formula i should use.

Homework Statement The plug in a bathtub is 10cm2 in area and is 0.8m below the surface of the water. What is the force of the water on the plug? Given Data: Area: 10cm^2 h: 0.8m too lazy to post attempts. sorry.