The direction of the force of friction would be given by the vector summation of its components along x and y axis, using parallelogram law. I draw it on my sketch in top left corner.
μ is not the mass, is the friction coefficient.
G is the gravity force, T is the friction force(with Tx and Ty its components), N is the normal force(on the inclined plane) and S is the tension force on the string.
I wrote the force equations on all 3 axes along with the equilibrium condition...
I have this problem.
I know G, alpha and mu. I need to know theta for equilibrium.
My problem is that in place of the thread I need to have a tension and when i write the equations of forces on all 3 axes and then I apply the conditions that Ff<=mu*N (Ff-friction force, N-normal on plane...