Recent content by Andrej.N

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    How many effusion stages required to increase the 235U to 4%

    Hi! Thanks alot! Then the expression for number of stages ##n## is: $$n=\frac{\log{\frac{4.0}{0.7}}}{\log{1.0043}}=407$$ My original solution to the problem was equivalent: ##y_{n+1}=1.0043y_{n}##. Where ##y_n## is the portion of ##^{235}U## at each iterration. I couldn't solve this...
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    How many effusion stages required to increase the 235U to 4%

    Homework Statement Uranium has two common isotopes with atomic masses of 238 and 235. One way to separate these isotopes is to combine the uranium with fluorine to make uranium hexafluoride gas, UF6, and then to let it effuse through a small hole. The natural abundance of the 235U isotope is...
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