Recent content by Andrzej

The reason is, you haven't got the final answer yet, as your formula still has an integrating constant C. Note that exponential function has a following feature e^a e^b = e^(a+b). Find the value of C in your function remembering that for t = 0 velocity was also zero V(0) = 0.

The relevant equations should be Ft = ma = W - kV W = mg a = dV/dt m dV/dt = mg - kV (1) This differential equation has an easy to guess special solution V = mg/k = const. The homogeneous equation for the one above is m dV/dt = -kV (2) Note that it is similar...