Recent content by andyL

here is a formal proof: You can show that \int t^n e^{-ts} dt = -s^{-n-1}\int_{st}^{\infty}x^n e^{-x}dx +c therefore \int_{0}^{\infty} t^n e^{-ts} dt =s^{-n-1}\int_{0}^{\infty}x^n e^{-x}dx =s^{-n-1} n!

I think it is not that difficult. let's call t_1=x and t_2=y and: <v(x) v(y)> = f(x,y) The integral I = \int \int dx dy f(x,y) is a 'volume integral' it should be called \int_{R(t)} f(x,y) Now notice that f(x,y) = f(y,x) , and since we want to integrate this over the box (bound...