Given P(cancer | smoker) > P(cancer) -- cancer is more prevalent in smokers -- does that declare smoking causes cancer? Not quite yet, because it's also possible P(smoker | cancer) > P(smoker) -- smokers are more common in cancer victims. Simpson's Paradox.
This leads to two classifications...
Then it should be possible to say that one of these two conditions holds:
P(A|B) > P(A) AND P(B|A) > P(B), the above stated scenario
the relationship measured in #1 isn't the case
Since the statement in #1 is a logical AND operation, there are four possible outcomes. So it can be represented...
Do you agree that P(A | B) is a causal relationship?
That is to say, P(A) given P(B) is a mathematical model of dependence, with a before/after status and causality?
Re-read the thread summary
Are there an infinite number of tangent lines with a slope of -50?
Or does that restrict the answer set to one unique line and set of coordinates?
I have a formula y=log(x)/log(0.9) which has this graph:
I want to find the intersection of this curve and a tangent line illustrated in this rough approximation:
The axes have very different scales, so the line isn't actually a slope of -1, it's just looks that way.
How can I figure out:
1)...
RE: "standard terms"
Variables are placeholders; they are nouns but they are not proper nouns.
They are always a mapping of the form a → b, such as "let Ω be the set of outcomes"
Use of these forums is not predicated on a specific naming convention.
Let's start with a model from the Mirror Universe.
In the Lab-O-Doom I conduct three trial runs of an experiment. I've got a bag of jelly beans and there's a yummy green one in there. There are also four other jelly beans in the bag.
And because I'm wearing a white smock and steam-punk eye...
The casino's offer of a gamble is a Bernoulli trial, the flip of a coin before the coin has been flipped. In this case a very unfair coin. The two possible outcomes are called success and failure to describe preference, such as winning a gamble. Each try is a movement from before we know the...
Let's take a look at that, because I may have made a tragic error. There are two quantities and a formula that uses them.
First quantity is confidence
confidence = 0.95
chanceToBeWrong = 1 - confidence
Second quantity is chance of success each try
chanceOfSuccess = 0.01
chanceOfFailure = 1 -...
Example problem
A casino offers you a gamble with a 1% chance of winning a try. How many tries will it take to win at least once?
Solution
For this example, I chose 95% confidence, a willingness to be wrong once in twenty...