Recent content by aniel

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    MHB Solving for x: sqrt(x+3)-2/4x-4 & 1-sqrt(cosx)/x^2

    Well I am really thankfull sir...its my pleasure to be part of this group, i hope i can learn more now and on. Congratulations about ur job here.Its a great thing . Thank you again !
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    MHB Solving for x: sqrt(x+3)-2/4x-4 & 1-sqrt(cosx)/x^2

    Than you sir yes i solved it and it is 1/16 my mistake its that i did in this way 4(x - 4/x) :/
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    MHB Solving for x: sqrt(x+3)-2/4x-4 & 1-sqrt(cosx)/x^2

    Welll thank you sir :) Yes we used the hospital rule and well i did some shortcuts at both of them but the book solution it doesn't coincides with my solution. well i went till here to both of them lim (x-> 1) sqrt (x+3) - 2 /4x - 4 = § lim (x->1) [sqrt( (x+3) -2] * [sqrt( (x+3) +2]/ (4x-4)...
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    MHB Solving for x: sqrt(x+3)-2/4x-4 & 1-sqrt(cosx)/x^2

    Im sorry i forgot where the x tends to go :/ lim (x-> 1) sqrt (x+3) - 2 /4x - 4 lim (x->0) 1- sqrt (cosx) / x^2 and I am so sorry taking your time but i get so confused with limits .
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    MHB Solving for x: sqrt(x+3)-2/4x-4 & 1-sqrt(cosx)/x^2

    the first one: sqrt(x + 3) - 2 / 4x -4 the second one : 1 - sqrt(cosx) / x^2 thnk you
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