Recent content by annnoyyying

oh... so the [H30+] should be the total concentration in the solution, initial: [HSO4-] = 0.001M, [H30+] = 0.001M, [SO42-] = 0M change: [HSO4-] = -x, [H30+] = +x, [SO42-] = +x equilibrium: [HSO4-] = 0.001-x, [H30+] = 0.001+x, [SO42-] = x giving the quadratic x^2 + 0.012x -0.000011=0, so x =...

Can you just tell me what's wrong with it? initial: [HSO4-] = 0.001M, [H30+] (ignoring what was formed from the first dissociation) = 0M, [SO42-] = 0M change: [HSO4-] = -x, [H30+] = +x, [SO42-] = +x equilibrium: [HSO4-] = 0.001-x, [H30+] = x, [SO42-] = x

Sorry, there was another typo the quadratic should be x^2 + 0.011*x - 0.000011. which still gives x = 0.0009226. Thank you very much.

Which part are you referring to? I just used MATLAB to solve the quadratic and still got the same answer for [H3O+].

Yes typo, it should be 10e-3. Ka = [H30+]^2/([HSO4-] - [H30+]) rearranging and letting x be [H30+] gives the quadratic equation x^2 + xKa - Ka[HSO4-] = 0. Well, you solve the quadratic by plugging into a calculator? x^2 + 0.011x - 1.e-5 = 0 giving x = 9.226e-4 My calculator has a function that...

Homework Statement How much does the auto - dissociation of water contribute to the pH a 10e+3M aqueous solution of sulphuric acid? Homework Equations Ka = [H30+][SO42-}/[HSO4-] = 1.1e-2 Kw = [OH-][H30+] The Attempt at a Solution Sulphuric acid is a strong acid in the first hydrolysis step...

I'm going to go with the quasi equilibrium route for the moment (i.e. -dF/dt = k3kc1kc2AF - (k-3 IJ)/kc4 ) for various reasons (there are other questions prior to this). The I and J in this answer cannot be eliminated right? I'll keep working on the non quasi equilibrium approach and i'll update...

I think the main problem I have with this is getting my head around the simutaneous equations... it would be much appreciated if you can give actual specific examples... I'm begging you. I keep on going around in circles. so so far I've eliminated D and H by taking C = D and G = H using the...

ok, so far I've got: -d[A]/dt = k1[A][ B] - k-1[C]^2 As B is simutaneously consumed and generated, -d[ B]/dt = k1[A][ B] - K-1[C]^2 - k-2[C]^2 + k-2[E][ B] = 0 As E is simutaneously consumed and generated, -d[E]/dt = k3[E][F] - k-3[G]^2 + k-2[E][ B]- k2[C]^2 = 0 d[J]/dt = k4[G]^2 - k-2[J]^2...

The reaction started with A, B and F. F is the reactant in the overall equation. Can you be a bit more specific? Like in "Some of the other concentrations are not independent so not only are some d/dt equal but some of the concentrations are equal, so the number of variables can be reduced."...

there was something wrong with the system when i was editing my reply which made it go all funny. using b's make everything into bold, using i's make everything italic... let me do it again: -d[A]/dt = k1[A][ b] - k-1[C][D] -d[ b]/dt = k1[A][ b] - k-1[C][D] -k2[C][D] +K-2[E][ b] -d[C]/dt =...

redone below

hmmm I've been trying for a few days and I still cannot get to the answer. There must be some key piece of the puzzle I've missed. Any tips?

Homework Statement Overall reaction: A + F = I + J (just take = as the equilibrium sign) It is first order in both A and B. The following mechanism has been proposed: 1. A + B = C + D 2. C + D = E + B (B is the catalyst) 3. E + F = G + H 4. G + H = I + J These are all...

OMG I feel so stupid. Thank you very much!