Recent content by Anon481516

Well, surprisingly enough, I never read that book, I don't know why. Nevertheless, I'll take a look at it. And yes, those examples and methods are reminiscent of those videos I've been watching. They may not be strictly algebra related, however the videos do contain what I think are the...

Mark44, Alright, thanks for the clarity. And I agree, I would need to go over Algebra again, perhaps more vigorously than before. Simon Bridge, Ah, I see, that step-by-step of the example helped out. For some reason I didnt see the 1 / x2 as what it really is, its difficult to explain...

SammyS, The x3 I got from taking the integral of 3x, which now that I think about it might be wrong. Mark44, Well, what I did there was remove the radical, and replace it with its equivalent 1/2 power, then I used that rule of xn+1 / n + 1 + C to get 3/2. The second problem I did...

Looking back at the solution process, it seems everything is written as it should be. For the first one, I never divided through by x, I simply changed the radical sign to a power of 1/2, then used one of the rules where xn+1 / n + 1 + C. I then multiplied the denominator so that it appears...

Homework Statement Simplify and Integrate: 1. ∫ √x (3x - 2) dx 2. ∫ 4x2 - 2 √x / x dx 3. ∫ (1 - x)3 dx The answers are : 1. 6x5/2 / 5 - 4x3/2 / 3 + C 2. 2x2 -4 √x + C 3. x - 3x2 / 2 + x3 - x4 / 4 + C Homework Equations The Attempt at a Solution 1...

Thats it? I thought there would have been more to it. Nevertheless, I'll still try and find some harder formulas to transpose for extra practice. Thanks for the help.

I got it now, thanks. As for my transposition, that's a good question, what did happen to the F... In the first transposition, everything was square-rooted, the G*m1*m2 and then that entire term is divided by the F. So: r = √(G*m1*m2) / F The second one: F = G*m1*m2 / r^2 F*r^2...

I didnt follow that third part: (√P)*R/√R You went from (√(P/R))*R = (√P)*R/√R <--- How did you get here? I tried isolating for r^2 in the force of gravity equation: F = G*m1*m2/r^2 r^2 = G*m1*m2 r = √G*m1*m2 As well as for m1: r^2 = G*m1*m2 r^2/G*m2 = m1...

Don't worry about that, I was just using it as an example to elaborate on my problem. It does make sense the way you did it. However, the way I was trying to do it, was trying to isolate the CO2 right at the beginning, trying to move it to the other side. I had similar problems when trying to...

Hello, I have a question about solving or isolating for variables in an equation. It doesn't need to be an equation, however, I've noticed my problems always appear when trying to transpose them. I have read through algebra concepts, but they only tell me what I already know regarding...

Alright, I think I understood that. Thanks to everyone who helped. I'll probably be back soon with more questions.

I see. From what I've learned, there are many cases such as precipitation reactions which form a solid from 2 aqueous solutions, usually determined by a table of soluble/insoluble compounds/elements. Combustion reactions generally involve O2 and form CO2 and H2O. Acid-base reactions...

Sammy, I'm not sure I followed that last part you said, "Then, (2x-5)3 (2dx) becomes (2x-5)3d(2x-5) which is u3du." Are you saying that the derivative of U3 is (2x-5)? I thought it was just 2. I may be confused by the wording.

Alright. But I noticed that there are many rules regarding integrating a function. Some rules look similar to one another, but you can only use one rule at a time, correct? From the previous example, you went from the actual function to 1/2 ∫ (2x-5) ... (2dx), then from there you used the...

But I still don't know how to find out what the product(s) would be from certain reactants. How do you know when to use synthesis, displacement, double displacement or decomposition? If I looked on the internet for random reaction equations and find: Fe + Cl2 ---> ? You could deduce that...