Recent content by Anonymous2258

Oh, okay! Then for calculating the 4-momentum of other particles besides the muon, what do I use for the energy component? Do i just the energy in the calorimeter? And one last thing, if I wanted to calculate branching ratios, is there any way to tell which kind of particles are in the detector...

Alright so I calculated the momentum of the muons as well as the energy so that's the 4-momentum? And I want to square the combined 4-momentums of the two decay particles, right? So to do that do I just use this formula http://en.wikipedia.org/wiki/Four-vector#Scalar_product And then that'll...

Okay so I calculated momentum in the x, y, and z directions, and added them from two muons in the same event together. You said I need to calculate the 4-momentum. Does that require knowing the energy of the muon? And once I have the 4-momentum, how do I square it from there? The only vector...

Can you use shell theorem to just treat it as a point charge, as long as the charge is symmetrically distributed?

Well for part 2, the river is flowing horizontally, so it does not affect the component of the boat's velocity perpendicular to the shore. You can act as though the river was still to get the amount of time it takes to get from one shore to the other. Since you want the horizontal distance, you...

So .3Br is the momentum perpendicular to the track and I need to find the x, y, and z components of the momentum? What 4-momenta am I adding, am I using the momenta from more than one event? Sorry, and I don't really understand how I'm supposed to use the 4-momentum in the energy mass momentum...

Oh okay gotcha...so just as a final check can you tell me if I am doing the calculations right? I'm using the total energy for a single event as E, in GeV (I already adjusted for the calibration). For pc I'm using .3Br where B is the magnetic field in Teslas and r is the XY radius in meters...

Thank you very much. I've seen that you can set m(v2/r) equal to the force from the magnetic field q(v×b) and get that, but since it is the cross product, am I going to have to use sinθ to get the magnitude? Or is the magnetic field always going to be perfectly perpendicular to the particle's...

I didn't know whether to put this in homework or in here because it is not homework but it is a question, so sorry in advance! I like to learn about quantum physics as a hobby, and I found this great link about working with actual particle accelerator data by an organization called Quarknet...