Recent content by anonymouz

ok thanks a lot for your help, andrevdh really appreciate it

help please!

^ for the equation that i came up with.. all i did was find t in terms of a, and substitute that in for the first equation then i squared the first equation and set it equal to the second equation then i solve for a i wrote the equation wrong up there. it's supposed to be: 2vi(-vi +/-...

i have the angle of the ramp, so i know the angle at which the cylinder fell once it rolled off the ramp but i don't know the angle of the cylinder's path when it hits the floor

also: are my calculations for accleration correct? (3 posts up)

what if the photogates weren't oriented vertically? the top photogate was oriented perpendicular to the ramp and the second photogate was oriented approx. perpendicular to the direction of the cylinder's fall

i have an idea..can someone check this? vf = vi + at vf^2 = vi^2 + 2ad d = vit + .5at^2 so you can solve for t in terms of a from the last equation then you can square the first equation and set that equal to the second equation. then you substitute in t and you can solve for a. i end up with...

does anyone know how to do this??

so it doesn't matter that the path that the cylinder travels in isn't straight? because the air makes the cylinder travel in a curve

My class did a lab where we roll a cylinder down a ramp (the end of the ramp was at the edge of the table). We placed a photogate timer right at the position where the cylinder fell off the ramp, and a photogate timer right at the position where the cylinder hit the floor. The information...