Recent content by Anuj Agarwal

Sorry. Here is my try: F =mxa hence a = f/m=3.2/1.1=2.9 A=v/s, hence s=v/a =7.5/2.9=2.58 Distance = velocityxtime = 7.5x2.58=19.3 m

Homework Statement A force of friction of 3.2N acts on a 1.1Kg puck while it is sliding along a horizontal surface. If the initial velocity of the puck was 7.5 m/s, how far will the puck travel before coming to rest? Homework EquationsThe Attempt at a Solution The answer is 9.7M. Tried...