So is this wrong then ??
F = ma
F = ti - 6t^2j + 3k
v = j + 2k
mass = 4 kg
ti - 6t^2j + 3k = (4)a
ti - 6t^2j + 3k / 4 = a
V = u + at
j + 2k = 0 + (ti - 6t^2j + 3k / 4) 1
4(j + 2k) = ti - 6t^2j + 3k
4j + 8k = ti - 6t^2j + 3k
= ti - 6t^2j - 4j + 3k - 8k
= ti - 6t^2j - 4j - 5k
I don't know how to integrate so is there any way around that for part 1 ?
I know how to do conservation of momentum but how do i take into account the angle 60 degrees ?
I never should have chosen applied maths as I have discovered maths is definitely not my thing but inh this test tommorow I...
(a) A particle of mass 4 kg moves under a force: F = 6t^2i - tj - 4k in Newtons.
Assuming that the particle is initially at the origin with velocity v = i + k in m/s, find its position after 1s.
(b) A ball of mass m travels with velocity 3 m/s and collides with a second ball with mass 2m at...