Recent content by apprentice213

teta=tan^-1(.3) teta=16.70 sine law: T/sin53=136.08/sin36.87 T=181 B:: teta=tan^-1(.4) teta=21.80is this right? T/sine36.87=90.72/sine53.13 T=68.04

last attempt to try .. hihi

for A: T-m1gsin53.13-μkm1gcos53.13=m1a m1g-T=m2a (T-1065.5)/136.08=a (1334.94-T)=90.72a T=1227.4 a=1.19 hehe! I am trying .. my memory is low :)

For B Fmax=0.4(90.72)cos36.78 Fmax=21.77 T=90.72sin36.87 T=1177.20 is this right?

for block A Fmax=0.30(136.08)cos53.13 Fmax=24.5 T=300(9,81)sin53.13 T=2354.4

for A: T1=136.08sin53.13/sin36.87 B: T2=90.72sin36.87/sin53.13 maybe il copy later I am weak .. grr! sorry sir thnx for intertaining

sory I am weak here in physics .. hihi! this? μm1g-T1=m1a1 m2gsin(teta)-T2=m2a2 so a=(g(μm1-m2))/m1+m2 last try .. hihihi sorry ..

i solve it again through dis solution.. so : T-m1gsin53.13-μkm1gcos53.13=m1a eq 1 T-505.44=90.72a eq2 T-m2gsin36.87-μkm2gcos36.87=m2a so T=577.27 a=-3.42for 2nd block: T-m2gsin36.87-μkm2gcos36.87=m2a eq 1 : T-505.50=90.72a T-m1gsin53.13=μkm1gcos53.13=m1a eq2 : T-1043.93=136.08a so...

i need to know if my formula is right or wrong? f wrong what part? or at beginning I am wrong ? what wod be the possible formula i used,,, thnx alot

thnx .. block A = 136.08 kg B=90.72 kg i already draw the free body block A will fall and block be will go upward.. the motion going to left. what would be posible formula to use in this problem? are my solution right?

help me please ! I am confuse what would be the fomula i`l use

Homework Statement Homework Statement [/b] am i right? please help me .. thnx Homework Statement the blocks shown in the figure are connected by flexible, inextensible cords passing over frictionless pulleys. at A, the coefficient fiction is 0.30 while at B, it is 0.40. compute the...

for A: Fmax=μk(m1)gcos53.13 54=μk(m1)gcos53.13 μk=0.03 T-300(9.81)sin53.13-μk(300)9.81cos53.13=(300)a eq(1) 200g-T=200a eq(2) subtitute (1) and (2) to find a a=-3.79 for block B: Fmax=μk(m2)gcos36.87 64=μk(m2)gcos36.87 μk=0.04 T-200(9.81)sin36.87-μk(200)9.81cos36.87=(200)a...

sorry it is kenetic..

Homework Statement Homework Statement the blocks shown in the figure are connected by flexible, inextensible cords passing over frictionless pulleys. at A, the coefficient fiction is 0.30 while at B, it is 0.40. compute the magnitude and direction of the friction forces and each block...