Recent content by ares25

Im going to restructure for base step: some f(x) and g(x) that are continuous, then max(f(x),g(x)) is also continuous. use the proof above to prove that. switch out f1 for f(x) and fN for g(x). then say that from the base step f(x),g(x) we can have max f1,f2 is continuous then fi,fi+1 is also...

On my other proof https://www.physicsforums.com/showthread.php?t=753405 I made it more general for the whole, but i believe its too general. I used that idea of max for whole but want to switch it to inductive. where the max of f,g is also continuous, then the max of any two are also...

Let f1,...,fN be continuous functions on interval [a,b]. Let g:[a,b] -> R be the function give by g(x) = max{ f1(x),..., fN(x)}. show that g is a continuous function i posted this earlier with one proof, I am trying another more general let ε >0 and arbitrary k. if f1(x) >...> fN(x)...

Let f1,...,fN be continuous functions on interval [a,b]. Let g:[a,b] -> R be the function give by g(x) = max{ f1(x),..., fN(x)}. show that g is a continuous function. I have let t ε [a,b] NTS g(x) is continuous at t if a≤t< b, then there exists a neighborhood Vt of t contained in...

ignore Sorry for the post. I'll take it down soon. Thanks for the help