Homework Statement
I've been given (or have calculated) the equation for damped SHM of a spring, and have been told to calculate the period...
I'm given that:
Forced produced by damper: b(dx/dt) where b = 16N/ms
k = 344.5N/m
m = 2kg
Homework Equations
I know that T = 2*pi/(W0)...
Ok, I've been thinking about this allll night (didn't get much sleep!)
I've come to a rather unsound conclusion... While more work done may be required to move the car up the hill (in the form of mgh), the action of gravity opposing the direction of motion will mean that LESS work will need...
Ah ok then, so the question is indeed badly worded... I'll be having strong words with my lecturer!
Ok, I think I am supposed to neglect air resistance, so there should only be Kinetic Friction in the wheels right?
Hmm yes, I haven't been able to encounter a problem similar to this anyway (it is all braking on a flat plane, not on an incline).
But I am probably being a little slow here, work done against friction is not the same as work done by friction?
and is it true to say that while the car is...
Of course, that makes a lot of sense. So that will be the total work done on the car? and from that I can calculate the Work done from the separate components (weight and friction)?
OK, well I understand that the total work done on the car is now equal to the change in kinetic energy, which must equal 1/2(mv^2) = 720kJ.
If I divide this by the distance traveled (40m), I can find that the overall force acting on the car is equal to 180kN.
However, if I calculate the...
Thank you:)
I am still a little confused. Why would it be -mgh? as I thought work would needed to have been done to elevate the car, therefore meaning it would be +mgh??
Homework Statement
A 900kg car is moving up a 15degree inclined slope at 40ms-1. The driver slams on the brakes, skidding to a halt 40m along the road.
Calculate the total work done by the car.
Homework Equations
This is what I am not sure of. As I am not told whether or not the...