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Aritro Biswas
Recent content by Aritro Biswas
Challenging Integrals in Calculus 1-2: Expand Your Problem-Solving Skills!
The answer is \frac{1}{2\sqrt{2}}\ln \left| { \frac{\sqrt{2}+{\sqrt{x^2+\frac{1}{x^2}}}} {\sqrt{2}-{\sqrt{x^2+\frac{1}{x^2}}}}} \right|
Aritro Biswas
Post #189
Dec 22, 2022
Forum:
Calculus
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Aritro Biswas
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