Yeah I'm sorry. I just forgot that though the falling current will induce emf in inductor it won't be able to flow bcoz the circuit is opened.
I'm sorry. My mistake. Thnks to all of you.
Now this whole question seems so stupid to me.
As far as opening the switch is concerned the current will not stop immediately. It will decay following the same rule of rise. Time constant not only limits the rise but also the decay.
Well the question goes like this..
An Inductor is connected to a battery through a switch. Why the induced emf in the inductor is much larger when switch is opened as compared to when the switch is closed.
I agree you tiny-tim and fatra2
@fatra2
Yes you are right that friction acts opposing the velocity and not applied forces. But here we are talking abt angular motion and not linear motion. This cannot be applied in rolling motion. See the reason below.
@tiny-tim
Thanks. After thinking...
A cylinder rolls up an inclined plane, reaches some height, and then rolls down. The directions of frictional force acting on the cylinder while descending will be up the inclined. But what will be the direction of frictional force when the cylinder is ascending??
UP or DOWN
Well, I think...
Well when we place the ring and sphere as you said that time
(i) Ring is outside the sphere so sphere can be treated as point like object with its mass concentrated at the centre (Let us say it S)
(ii) Now break the ring into elementary parts each elementary part will be at a distance of r...
Well, the answer is (As far as i think)
This equation applies to "point like" bodies
if two (POINT LIKE) bodies have zero distance between them that means they are located at the same location.
So they will behave as single object and this unified body (which is again POINT LIKE) will not...