Recent content by as11

I don't think you have to use an equation; it's asking for the average emf and emf = -dflux /dt and dflux= flux2 - flux1 , but flux2 = 0 because the current goes to 0 (stated in problem) and dt is given in the problem

My apologies. So B(inside solenoid) = \mu0*n*I = (1.2566 x 10-6)*(1800)*(4.0A) = .009048 T Area loop = \pi*r2 = \pi* (6.25 x 10-4) = .0019635 m2 so, if \Phi= BA = (.009048 T) * (.0019635 m2) = 1.7766 x 10-5 but this answer was marked incorrect.

Homework Statement A solenoid has 1800 turns of wire and is 125 cm long and 10.0 cm in diameter; see Figure P.14 (attached). A circular wire loop of diameter 5.0 cm lies along the axis of the solenoid near the middle of its length as shown. (a) If the current in the solenoid initially is...

Problem: One (1.00) mole of an ideal diatomic gas (with = 1.40) initially at 20.6°C and 1.00 atm pressure is taken around the following cycle: Path (1): an isochoric increase in pressure until the temperature of the gas is 159°C and the pressure is P; Path (2): an adiabatic expansion until...

Hi, I'm trying to figure out the same problem. What does it mean for there to be .99 atm pressure outside vs. inside, in terms of solving a problem? Conceptually, is it that the pressure outside is pushing against the top of the cylinder, but the pressure inside is greater than the outside...