The answer is 0.94 J/K. But I have no idea how he got there.
the C for alum from our book is .22 so I got .22ln(324K/286K) + 1ln(324K/331K) = .006071 J/K
I am still missing something aren't I?
Using your formula I have 691.796 J/K from 900ln(51/13) + 4186ln(51/58) but I am still wrong in my answer. Am I supposed to convert to Kelvins? or use kcal/kg?
120 g insulated aluminum cup at 13°C is filled with 140 g of water at 58°C. After a few minutes, equilibrium is reached.
I found the final temperature to be 51°C.
But I am having trouble finding the total change in entropy.
I was using
13°C = 286.15°K
51°C = 324.15°K
58°C =...
A 20.0 -kg box having an initial speed of 1.0 m/s slides along a rough table and comes to rest.
Estimate the total change in entropy of the universe. Assume all objects are at room temperature (293 K).
I don't understand how to answer this problem. It feels like I wasn't given enough...