AMC Question HARD!
While doing the Year Eight AMC (Australian Maths Competition), I came across this diffucult question...
(By the way, this isn't homework :P)
"I have a list of twelve numbers. The first number is 1 and the last number is 12. Each of the numbers is one more than the average...
[SIZE="1"]EDIT: I think the French don't have this problem …
they distinguish between (pardon my French! :smile:) …
"multiplier par rien" and "ne multiplier par rien"
very true :)
i think i get it now...
pretty much 1 plus 1 always equals 2
and all of the so called "alternate solutions" break one rule of mathematics or another.
is this a good summary?
thanks for all of your fantastic help