Recent content by ashers

THANK YOU SO MUCH! I realized i was making a multiplication error early on in the problem and this is why i could not solve it correctly. You're explanation helped so much! thanks again!

so should i multiply it out by -2 so that the answer becomes 8?

the answer becomes -4

but i still can't seem to figure out how to make X^2 - 10x + 21 pass through (5,8)

so wait now all i have to do is multiply the entire formula by one constant until f(5)=8?

thanks!

well i tried multiplying x-3 and x-7 to get the equation and i got x^2 - 10x + 21. but, if you plug in 5 as x it does't equal 8. and also if point (5,8) is the vertex that means the parabola would open downwards, which makes the equation negative. I'm still really confused though :/

i actually have no idea how to move on from there because we haven't learned that formula. I am in CP Pre-calc in high school and the simplest solution would be great. I am not very good at math and this is a review of stuff we learned from september :/

1. Write an equation of the quadratic function f whose graph has x-intercepts 3 and 7 and f(5) = 8. 2. I really don't know where to go from here :frown: 3. obviously, is the x-int. are 3 and 7 that means they are points (3,0) and (7,0). Also, f(5) = 8 becomes the point (5,8) which i have found...