Also the peak emf is E(o) not simply E so you can use the following equation:
E(o)* sin(wt) = NAB w sin(wt)= E
This simplifies to:
E(o) = NAB*w
Solve for w.
I think I might be confused on some conceptual issues on this problem as I can't really come up with a way to get a numerical answer on anything in this problem. Please help me with any guidance or clarification.
The Problem:
A square (2.3 cm on each side) wire loop lies 9.0 cm away from a...
I think I might be confused on some conceptual issues on this problem as I can't really come up with a way to get a numerical answer on anything in this problem. Please help me with any guidance or clarification.
The Problem:
A square (2.3 cm on each side) wire loop lies 9.0 cm away from a...
I think what is possible and what isn't isn't the question here it was a homework problem that discussed I guess why batteries die in cold weather. But regardless he wanted how much charge is pumped in those 24 seconds which is drum rolll... 10800 Coulomb's!
Your guess is as good as mine. Personally I think he makes this stuff up but doesn't excuse me from homework assignments.
I guess I kinda looked at charging capacity as the battery's ability to hold on to charge. So I went on to figure out how much charge the battery can pump in 24 seconds...
Here I'll give you the question as written:
A starter motor in an automobile is an impressive piece of machinery. When a cold engine is started, this motor can draw 450 Amps of current from the 12 Volt battery.
a.) What is the effective resitance of the motor?
b.) If the starter motor turns...
Anything of the slightest bit of insight? Am I helping myself if I find the charged cranked out in those 24 seconds? And then use that charge to find the Work done? Am I on the right track at all?
So is a battery considered a capacitor? And if so does finding the charging capacity imply finding the capacitance? If not, what sort of value am I looking for for the chraging capacity(i.e. energy, potential, electric potential energy)?
It was a multistep problem where resistance was found to be 0.027 ohms in a car battery that is possible of cranking out 450 amps in a cold engine. Then the part I was stuck on was finding the charging capacity if the engine was cranked for 24 seconds it was completely drained.
I have a homework problem that asks me to find the charging capacity of a battery. I wasn't sure how to find this or what equation to use. I wasn't sure if the charging capacity was an equivalent to the capacitance. Can someone point me in the right direction?
Note: I am given it's a 12 V...
Yes Thank You, I suppose I am a little rusty on some of the basics. Plus, I tend to get a little confused setting up my problems. I was never really good at Physics. But Thanks a Million you were a great help!