Recent content by asqwt

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    Boulder on a hill (Vectors and components)

    im scared i might be wrong... but.. so if i rotate it to make the slope my x-axis is the x component w cos (90-theta)? since I am not using the angle given?
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    Boulder on a hill (Vectors and components)

    assuming you mean the magnitude is 16. vertical is 16 (sin 20) and horizontal is 16 (cos 20)
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    Boulder on a hill (Vectors and components)

    woh i never did dot products. sorry I am making this hard for you when it is supposedly simple = \ i feel like a retard. but can i get a few things straightened out? so is the VECTOR of this problem is the weight of the rock going downward? you want me to rotate my drawing so that the...
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    Boulder on a hill (Vectors and components)

    the component is always the original magnitude time cos of the angle … so for one direction it'll be cos(a), and for the other it'll be cos(90°-a) = sin(a) … how did you get those? i didnt read that in my book :(
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    Boulder on a hill (Vectors and components)

    you want me to rotate the diagram till the vector of the rock... (which is pointing down) is horizontal? so rotate right 90 degrees? am i solving for the length of the slope? sin a = w/length of slope.
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    Boulder on a hill (Vectors and components)

    i know a vector is made up of an x component, and a y component. but that is when the vector is in a diagonal direction.
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    Boulder on a hill (Vectors and components)

    Homework Statement A boulder of weight "w" rests on a hillside that rises at a constant angle "a" above the horizontal. The boulder's weight is a force on the boulder that has a direction vertically downward. In terms of "w" and "a", what is the component of the weight of the boulder in the...
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