Recent content by Astoreth

Thanks! I am glad to be here :)

Hi folks: I am really bad at introductions. So I'll see what I can do. I am physics/chemistry (mature) student who is still deciding what to do with the future. I have a background in...well, all sorts really: from science technician, to real state agent, to waitress, to bingo moderator...

Hello: when I finally decided to study physics, I've noticed that my maths weren't all up to speed due to a background in humanities. The most helpful website I found for maths is https://www.khanacademy.org/ (of course free). Which is a really good source to study maths from the very...

Thanks, Chet :) Is good to be here

Hello: sorry about that. No, the answer was not incorrect, but given this: I thought I'd help. I am sorry if I overstepped. I was only trying to help Also, i didn't noticed that it was marked as resolved. Again, am sorry

I think the answer might be along the lines: PV=nRT for adiabatic process PVgamma= A V=nRT/P so fitting this into the equation: P(nRT/P)gamma then you get TgammaP1-gamma=A/(nR)gamma Use the same principle to substitute P=nRT/V into the adiabatic condition hope that helps Sorry about the...