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The volume of a solid rotating about a different axis
Well, the problem didn't specify anything like that. All I received was the equation, the interval and what axis it's rotating about, so I just presumed that's what the graph would look like for the problem. I'll try working it out with inner radius as 0 though, thanks!- atomibay
- Post #5
- Forum: Calculus and Beyond Homework Help
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The volume of a solid rotating about a different axis
Yeah, I've tried graphing it but even while I was looking at it, I'm still confused as to how to read the inner radius and the outer radius. I figured that the inner radius is (y+1) and the outer is \frac{1}{4+x^2}, right? I'm not sure about the area though.- atomibay
- Post #3
- Forum: Calculus and Beyond Homework Help
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The volume of a solid rotating about a different axis
Homework Statement y = {\frac{1}{4+x^2}} on the interval [0,2], revolving about y = -1 Use either the disk/washer or shell method to find the volume. Homework Equations v = pi\int (outer radius)^2-(inner radius)^2\,dx v = 2pi\int (radius)(height)\,dy x = \sqrt{\frac{1}{y}-4}...- atomibay
- Thread
- Axis Rotating Solid Volume
- Replies: 4
- Forum: Calculus and Beyond Homework Help