Recent content by AussieBec

Homework Statement ok so it isn't exactly a problem. i just need to know some equations i can use in relation to a hydraulic breaking system i don't mind what, but if someone could just give me a calculation i can do for an assignment that would be great. thank you Homework Equations...

ahhh lol. i completely forgot to do that :P ok so it's = 655v1f^2 + 1541917.527 + 860.86v1f^2

oh ok. thank you. i did it all again and i think i got it right this time :D thanks for your help!

ok, but then i get ... -907379.0103= 1515.86v1f^2 -598.59 = v1f^2 square root(-598.59) = v1f and you can't square root a negative and get a real answer. so i don't know what it is, but i must have done something wrong

ok so i just did it with squaring 1.31v1f and it worked out as 209.91 and i think it was m/s which seems wrong. considering that they were originally traveling at 22.2m/s and 27.78m/s so i don't know if that's right

ok, well i figured out that (m1v10+m2v20-m1v1f)/m2 = v2f i then substituted m1=1310kg, m2=1001kg, v10=22.2m/s, and v20=27.78m into the equation and got v2f = 56.83 - 1.31v1f (i wasnt sure if you could completely eliminate the 56.83, and i couldn't figure out how to without...

gah. i think i did something wrong... i used the values... m1=1310kg, m2=1001kg, v10=22.2m/s, and v20=27.78m/s and i got to the last step on my equation, and i can't finish it off... -1381.68 = v1f^2 and you can't square root a negative number and get a real answer

wait! then you would work out the equation and then sub it into the energy one right? so youd have a number then v1f and then you could use that in the energy equation

ok so i rearanged the momentum equation and got... (m1v10+m2v20-m1v1f)/m2 = v2f does that look kinda right? also, would the m2 in the m2v20 cancell out?

ok thatnks, i'll try that. and ill post again if i have any problems

oh ok, so i have: 1/2 m1v1o^2 + 1/2 m2v2o^2 = 1/2 m1v1f^2 + 1/2 m2v2f^2 and m1v1o + m2v2o = m1v1f + m2v2f then i would find a value for say v2f in terms of v1f and then plug that into the first equation? would that work?

um no... i have no idea where the second equation comes from :/

:D thank you. ok so now i have 2(1/2 m1v1o^2 + 1/2 m2v2o^2) = 2(1/2 m1v1f^2 + 1/2 m2v2f^2) which simplifies to m1v1o^2 + m2v2o^2 = m1v1f^2 + m2v2f^2 here is where i get stuck, i don't know how to get either v1f or v2f by itself, if i take either the m1v1f^2 or m2v2f^2 to the LHS i...

ok so, i have an assignment due tomorrow, i know, late starting, but i can't figure out how to rearange the kinetic energy and momentum equation to get the v1f and v2f i know that you have to find one term in the for of the other, but i don't know how to rearange my equation so that i have...