Argh, having typed the last response and ruminated on what I said, I think I have the solution. At any given z_0, the net electric field is due to the regions of the slab -L < z < -z_0 and z_0 < z < L. Any charge within the region |z|<|z_0| will cancel, giving the strongest electric field for...
Thanks for the input, dynamicsolo. This was also my opinion at first glance. Taking a step back, looking at the system in the most basic terms, we have a "slab" of positive charge in the region z>0 adjacent to a "slab" of negative charge in the region z<0. As in a parallel plate capacitor...
Homework Statement
We have a charged, insulating slab of thickness 2L in the z direction, and very large (read infinite) in the x and y directions. The slab contains a charge per unit volume that varies linearly from -\rho_{0} to \rho_{0}, from one side of the slab to the other...