Rifle muzzle at 5ft shoots up at 45 degrees at 3000ft/sec (no wind, etc.):
-5=0+2121ft/sec*T-15.16ft/sec^2*T^2
T=139 sec
X=0+2121ft/sec*139sec=294819ft
But, I never figured out how to get Ymax?
(and it's time for a lunch break... all this math is making me crazy!)
Not anymore! You need an emoticon for "my head is about to burst!"
Well, going online, I found the solutions to be:
-.005653 (disregard)
72.16
So T=72.16
x = x_0 + v_0 t + (1/2) a t^2
x=0 + 353.56m/sec*72.16sec+ 4.9m/sec^2*(72.16sec)^2
x=25512.89m+25514.62m=51027.51m=51.027km=no...
-2=0+353.56+0.5(-9.8)T^2
-4.9T^2=-355.56
T^2=+72.56
T=8.52 sec
x = x_0 + v_0 t + (1/2) a t^2
x=0 + 353.56m/sec*8.52sec + 4.9m/sec^2*72.56sec^2
x=3012.33m+355.54m
x=3367.87m
The Ymax I thought I would figure by dividing the time in half, but being a perfectionist, how would I account...
The final vertical displacement would be -2meters. Am I missing something? I have no idea ho high it went nor the time in flight (both of which would be related to 9.8m/s^2) nor the distance traveled (which would be dependent on the time in flight).
What am I mssing here?
Yes, I am trying to find the range, which would be x. The original x=0 (the muzzle of the cannon), the original y=2 (height of muzzle... i used 5 feet, let's just call it 2 meters). The final x (the displacement) I do not know.
The first four I understand.
The fifth,
x = x_0 + v_0 t + (1/2) a t^2
I believe says that the x-coordinate will be the original starting point (x=0 in this case) plus the original velocity multiplied by time plus 1/2 acceleration multiplied by the time squared.
In this case, I could...
So we start off with an initial x and y velocity of ~353m/sec; the x component will stay that throughout the time in flight (since we will be ignoring wind resistance and other effects). The Y velocity will start to bleed off at a rate to be determined somewhow by that 9.8 m/s^2 thing, but I...
Arrrgh! You are going to make me think?
Oh, well! It is either the sin or cos of 45. Maybe it's pythagorean's theorem? Is it 353.56 for initial x and y?
(Honestly, I used to get 100% on my physics tests!)