Given that U = (3/2)PV does this mean that ΔU = Δ(3/2)PV for an ideal gas? Hence when finding the change in internal energy using a P-V diagram, can we simply apply this equation instead of using ΔU = Q+W?
Homework Statement
We did a physics practical in which a sealed syringe is compressed and pressure and volume of air inside is recorded. Given P=k/v, the gradient of the graph of P against 1/v is the constant,k. How would the value of k change if the same experiment is conducted at a higher...