Recent content by AwooOOoo

Fixed it... equation 5 was wrong ##r = \sqrt{\frac{a^2b^2c^2}{b^2c^2{sin^2\theta}{cos^2\phi}+a^2c^2{sin^2\theta}{sin^2\phi}+a^2b^2{cos^2\phi}}} ##

Hi, I have been referencing this (https://www.physicsforums.com/threads/radius-of-ellipsoid.251321/) previous post to calculate the radius of a Triaxial Ellipsoid (a>b>c), but I'm running into some issues. Let 0 ≤ ϕ ≤ π 0 ≤ θ ≤ 2π and x=r * cos(θ) * sin(ϕ) (1) y=r * sin(θ) * sin(ϕ)...