Oh wow...so since SG is 1.0, the weight of the 2 legs would be equal to the water displaced, right? So Fb = 24, and divided between the 2 legs would be 12 kg.
That was a lot easier than I made it...thanks so much!
"A 78-kg person has an apparent mass of 54 kg (because of buoyancy) when standing in water that comes up to his hips. Estimate the mass of each leg. Assume the body has SG = 1.0."
So, the original question asks for me to estimate the mass of each leg of a person whose body past the hips is covered by water. They give me the person's actual weight and the apparent weight as well as the specific gravity of the body.
I understand w' = w - Fb, Fb = F2 - F1 where F = PA or...