Would the answer goes as follows:
Let A be the event of the bag containing 50 Red balls, 50 Blue balls and let P(A) = p
Let N be the event of picking N red balls and no blue balls.
Suppose I have picked n red balls. Then P(N) = 1.
Hence P(A|N) = P(N|A)P(A)/P(N) = p x P(N|A). Since we...
Thank you for your replies.
@micro mass: Thank you for the link. I see how it is relevant however, since I do not know the specific number of red and blue balls in the bag I don't see how I can use this distribution.
@Stephen Tashi: Thank you for your illustrations. I got my head round...
Hmm, many thanks for your answer. It certainly provides some relief but also makes things a lot more complicated for me as in the problem I am working on (which is analogous to problem I have given here) it is hard to determine p(0).
Given the bag contains 50 red balls and 50 blue balls...
There is a bag in front of me. I am told it contains 100 red balls or 50 red balls and 50 blue balls. If I pick n red balls from the bag and no blue balls what is the probability as a function of n (p(n)) that the bag contains 50 red balls and 50 blue balls. Of course, if n is greater than 50...