Recent content by baby_garfield

  1. B

    Oh I feel so insignificant help me

    the first one is kinda confusing cause the way you typed it. but the second one is not hard. since both sides have the base of 5, and they are equal, that means the exponents have to be the same. so 24x^2=-71x+30
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    Factor Equation: (1-v^2/c^2)^3/sqr((1-v^2/c^2)^2)

    isn't it just 1?!
  3. B

    Solving y=8x-2x^2 and y=4x-x^2 for x - Thank You!

    no! it's not! it's right! (sorry for not being sure )
  4. B

    Solving y=8x-2x^2 and y=4x-x^2 for x - Thank You!

    never mind! that was wrong
  5. B

    Solving y=8x-2x^2 and y=4x-x^2 for x - Thank You!

    y=8x-2x^2--> 8x-2x^2-y=0--> 2x^2-8x+y=0 use quadratic formula!
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    Help~ Don't remember what the point of tengency is.

    Here is the problem. f(x)=x^3-18x^2=105x-146 and 2 is a real zero. now, through the point (2,0), draw a line that is tangent to the graph at a point to the right of the low point at x=7. find the slope of the tangent line using x=2 and the point of tangency. and here is the graph.
  7. B

    Find Equation of Circle: A(2,2) & B(5,3), y=x+1

    Plug the two points in the equation and then you get an equation with p and q which should look like 3p+2q=13. since the center is on the line y=x+1, and the center of the circle is supposed to be (p,q). So q=p+1. then solve for the equation.
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