I'm going to blame it on the embarrassingly long amount of time I've been looking at this problem. I just solved, finally. Thanks a lot! I really appreciate it!
(x+2)(x-2)/(x-2)
(x+2)
x->2 = 4
That would mean that...
4a - 2b + 5 = 4
4a - 2b = -1
4a = 1/2b
a = 1/8b
But plugging that into 10a - 4b = 7 gives me...
10(1/8b) - 4b = 7
(5/4)b - 4b = 7
(-11/4)b = 7
b = -28/11
...Okay, that isn't right...I did this problem 3 different times and came up with...
Homework Statement
Find the values of a and b that make f continuous everywhere. (Enter your answers as fractions.)
Homework Equations
The Attempt at a Solution
lim x->2 (x2-4)/(x-2) = 0
lim x->2 4a - 2b +5
lim x->3 9a - 3b +5
lim x->3 12 - a + b
4a - 2b + 5 = 0
4a...