Recent content by baddin

Ah, did you just arbitrarily pick the upper limit which is larger than f(x)?

Thanks hilbert2, I see what you are saying. I also just found another way to do it, ill post it: Multiplying the expression by (sqrt(x^2+1) + x)/(sqrt(x^2+1)+x) you get lim(1/(sqrt(x^2+1)+x) = 0. I see that you have used the sandwich theorem, and i suppose that is an easier way to do it. I am...

Hey guys, I have been trying this question for 40 minutes and I can't get the answer. Evaluate lim as x approaches positive infinity(sqrt(x^2+1)-x). I tried the La-Hopital's rule, but even then I still get inf/inf. I know there is an algebraic manipulation I need to make, but I keep getting...

Because the values of one_vote_array change each time the function read_one_vote gets called

I still am finding it confusing though, can't I use the same array with different value and set it to each node?

Ok, I did what you said, and it works now. Thank you very much.

But my function read_one_vote changes the contents of the array one_vote_array everytime it is called, so shouldn't that array be different for each node?

I have pasted my code here : http://pastebin.com/nMNarH9i It is in language C. Basically, I am reading in 5 numbers at a time. Putting these numbers in array one_vote_array. Then I need to put this array in a structure vote_node. I also then change my next pointer in the structure to head...

Okay thank you very much for your help =)

Ok, then I should find T(1,0,0,0), T(0,1,0,0), T(0,0,1,0) and T(0,0,0,1) right?

1. Give information Let T: P3 ---> P3 be the linear transformation described by: T(p(x))=p(x+1)+p(2-x). Find the matrix of T with respect to the standard basis b {1,x,x^2,x^3}. The Attempt at a Solution I found the transformations on the standard basis b: T(1) = 2 T(x) = 3 T(x^2) =...

OH my fault, I see they are linearly independent. So could I generalize this and write span(S) = {a(1,1,2) + b(1,-1,2) + c(0,0,0) + d(0,2,4) + e(-1,3,6)} given a>0, b<0, c,d and e are any real numbers?

So for x<0 The x vectors look like(x,-x,-2x) and for x>0 the x vectors look like (x,x,2x).

So for any values of x I pick. the x vectors will be linearly dependent and they cannot form my span? So would that mean the span(S) = span of linearly independent independent vectors in S. So span(S) = <a(0,2,4)+b(-1,3,6)>?

Homework Statement Give S = {(x,|x|,2|x|) | x \in R} \bigcup {(0,2,4),(-1,3,6)}, find span(S) Homework Equations I know that span of a finite set of vectors is given by <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, where a,b,c are any real numbers. Can i use that same way to find the span of this...