Is the span of the infinite set S the same as the span of a finite set?

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Homework Help Overview

The discussion revolves around the span of an infinite set of vectors defined as S = {(x,|x|,2|x|) | x ∈ R} ∪ {(0,2,4),(-1,3,6)}. Participants are exploring whether the span of this infinite set can be treated similarly to that of a finite set.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the linear dependence of the vectors generated by the variable x and whether they contribute to the span. There is discussion about the representation of these vectors for positive and negative values of x.

Discussion Status

Some participants have offered insights into the linear independence of certain vectors and are considering how to express the span in a generalized form. There is ongoing exploration of the implications of including dependent vectors in the span.

Contextual Notes

Participants are considering the constraints of vector representation in three-dimensional space and the implications of linear dependence on the span of the set. There is a recognition that the span should ideally consist of independent vectors.

baddin
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Homework Statement


Give S = {(x,|x|,2|x|) | x \in R} \bigcup {(0,2,4),(-1,3,6)}, find span(S)

Homework Equations


I know that span of a finite set of vectors is given by <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, where a,b,c are any real numbers. Can i use that same way to find the span of this infinite set.

The Attempt at a Solution


Is the solution same as the vector span for a finite set like span(S) = <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, or is it something else?
 
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baddin said:

Homework Statement


Give S = {(x,|x|,2|x|) | x \in R} \bigcup {(0,2,4),(-1,3,6)}, find span(S)



Homework Equations


I know that span of a finite set of vectors is given by <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, where a,b,c are any real numbers. Can i use that same way to find the span of this infinite set.


The Attempt at a Solution


Is the solution same as the vector span for a finite set like span(S) = <a(0,2,4) + b(-1,3,6)+c(x,|x|,2|x|)>, or is it something else?

Lots of those x vectors are multiples of each other. I would start by looking at what S looks like for x > 0 and x < 0.
 
So for any values of x I pick. the x vectors will be linearly dependent and they cannot form my span? So would that mean the span(S) = span of linearly independent independent vectors in S. So span(S) = <a(0,2,4)+b(-1,3,6)>?
 
baddin said:
So for any values of x I pick. the x vectors will be linearly dependent and they cannot form my span?

I don't know what you are trying to say here. I will say it again: what do the x vectors look like if ##x > 0## versus ##x<0##? You might start by actually answering that question.
 
So for x<0 The x vectors look like(x,-x,-2x) and for x>0 the x vectors look like (x,x,2x).
 
And if you factor an x out of each what happens? And why do you say they are linearly dependent?
 
OH my fault, I see they are linearly independent. So could I generalize this and write span(S) = {a(1,1,2) + b(1,-1,2) + c(0,0,0) + d(0,2,4) + e(-1,3,6)} given a>0, b<0, c,d and e are any real numbers?
 
baddin said:
OH my fault, I see they are linearly independent. So could I generalize this and write span(S) = {a(1,1,2) + b(1,-1,2) + c(0,0,0) + d(0,2,4) + e(-1,3,6)} given a>0, b<0, c,d and e are any real numbers?

Is that b vector correct?

Usually when you are asked to describe a span you wouldn't include extra vectors that don't add anything. Since these are 3D vectors you would expect at most to need 3 vectors and maybe fewer to get an independent spanning set. And remember that a span automatically doesn't restrict the multiplying constants to positive or negative.
 

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