Maybe...
Okay so from the conservation of momentum I get
## v_f=(m_1v_0)/(m_1+m_2) ##
and plugging that into the original equation
##1/2m_1v_0^2-1/2(m_1+m_2)((m_1v_0)/m_1+m_2))^2=1/2kx_{max}^2##
which I then chose to solve for
## x_{max} ##
and got
## x_{max}^2=1/30 ##
And since I had...
alright fair enough.
I have KEi-KEf = Loss
and KEf = KEi - PEf (so essentially the final potential energy is equal to my loss in kinetic energy.
Then I get
1/2mv0^2 = 1/2(m1+m2)vf^2 - 1/2kxmax^2
But I have two unknowns in this equation, xmax and vf
should I also conserve momentum, solve...
Homework Statement
Mass 1 (M1=1 kg) slides on a frictionless surface at v0=1 m/s toward a mass (M2=2 kg) with a spring bumper of force constant k = 20 N/m. The two move together at vf at the instant that the spring is compressed to its maximum x. Find the loss in kinetic energy (KEi-KEf).
I...