Recent content by Badger94

Yes! Good catch. I promise on paper I didn't have these mistakes so I still am getting 1/3 as my answer

You are wonderful! Thank you

My mistake, I just meant ##v_f## Fixed

^^^^^ good heavens. Clearly not getting this LaTex thing either

Maybe... Okay so from the conservation of momentum I get ## v_f=(m_1v_0)/(m_1+m_2) ## and plugging that into the original equation ##1/2m_1v_0^2-1/2(m_1+m_2)((m_1v_0)/m_1+m_2))^2=1/2kx_{max}^2## which I then chose to solve for ## x_{max} ## and got ## x_{max}^2=1/30 ## And since I had...

alright fair enough. I have KEi-KEf = Loss and KEf = KEi - PEf (so essentially the final potential energy is equal to my loss in kinetic energy. Then I get 1/2mv0^2 = 1/2(m1+m2)vf^2 - 1/2kxmax^2 But I have two unknowns in this equation, xmax and vf should I also conserve momentum, solve...

Homework Statement Mass 1 (M1=1 kg) slides on a frictionless surface at v0=1 m/s toward a mass (M2=2 kg) with a spring bumper of force constant k = 20 N/m. The two move together at vf at the instant that the spring is compressed to its maximum x. Find the loss in kinetic energy (KEi-KEf). I...