Recent content by bahamut

It is called what what effect(I don't know how to say it in english) The frequency the blood receive isf1=f(sound)*(V(sound)+V(blood))/V(sound) The frequency blood reflect and mixed with the original Ultrasound is f2=f1*V(sound)/( (V(sound)-V(blood)) So...

Beacause the speed is not changing,so the accelerate is always zero for the in air part. You ditribute it into two part. The force1 at every specific time is just to counteract the gravitation of the in-air part of the rope. Since the mass of this part is m(x)=M*(x/L); So its gravitation is...

I wonder if there is something wrong on your computer

You have made a mistake,im afraid. Even if you find that R=-1,it is just a mathmatic form. R is always positive,you can just say R=|1/2cos(theta)| If still don't understand,contact me at wangkehandsome@hotmail.com,I will be glad to anwser it for you and even be more glad if you point out my...

There is a fuction describing this. As far as I can remember,it is A=A(max)*e^(-wt)*cos(wt+...) Since you know that "In half a minute its amplitude decreases from 50cm to 5.00mm." you can find how much is that "w".But I am not very sure,may I can tell you the accurate one if you contact me at...

Actually,you are not right. T=t/r=32/10=3.2 second.

v(t)=gt;(1) s(t)=(1/2)gt^2;(2) g=10m/s^2; so v(3)=30m/s,v(6)=60m/s,v(9)=90m/s; and s(3)=45m,s(6)=180m,s(9)=405m. a=F/m=20/60=1/3 m/s; v(final)=at=8/3 m/s; V(average)=(1/2)v(final)=4/3 m/s; S=v(average)*t=32/3 m; M=F*L*cosa=20*0.6=12 N*m fs=(delta)E=(1/2)mv^2; so...

Will it be 40*1000?

How do you know that?Can you find a simple evidence for your theory?

There is a easier way to solve this problem My english is poor,but I guess you can understand my idea easily. Firstly,we let g(x)=-(2/3)x+h be our one line of rectangular when g(x)=0,x=(3/2)h; when x=0,g(x)=h; so the two other line of rectangular are p1(x)=(3/2)x+h and p2(x)=(3/2)x-(9/4)h...

Just draw a triangle,then you measure it! It may not be very accurate,but it is a way!