Recent content by BananaJelly

Yeah, thanks. My intuition regarding mechanical engineering and forces is lacking.

Sort of. But I'm also just talking about a general cantilever fixed on a wall at one end, and the forces or reactions at the wall end.

I don't know. But based on what I looked up, there would be a moment, vertical force, and a horizontal force.

I meant there's no vertical reaction. Or am I wrong?

Thanks! It covers it a little bit, but I mainly learned how to draw them from a few youtube videos. The review manual lacks concepts. For the case with the wall, I was thinking that there was no reaction at the wall, so I wasn't sure how to approach it. But since there is a load, I guess you...

Okay. That's what I thought, but I didn't understand the concept behind it. So if it is a triangular load, then it would be M = (1/3)*(1/2)wL or a M = (2/3)*(1/2)wL with w = mg [=] Newtons depending on how the triangular load is distributed, correct? I will need to look up how to draw a stress...

I assumed the mass was distributed uniformly along the beam. I don't know how I would draw the shear force and moment diagram in this case, since the force is applied at an angle. I'm really just trying to understand why you have to divide mgL by half to solve for the moment of the beam due...

This is a problem from Michael Lindeburg's FE Review Manual. It is in Chapter 20, Number 11 if you have the book. PROBLEM: There is a picture of a cantilever 2 m in length attached to a wall. There is a force applied at a 30 degree angle from the horizontal at the free end of the beam...