Recent content by barbiegirl42
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
I managed to find the worked answers. You were right in not including the length. I only got mixed up with the dividing. Now I see that you first divide by 2 then divide by sin 5- barbiegirl42
- Post #10
- Forum: Introductory Physics Homework Help
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
But I'm not finding the vertical component of the tension neither the horizontal, I'm finding the tension along the wire. Why test the validity of the answer though. I would assume in a printed book that looks pretty valid to me that the answer would be right. I already know the force downwards...- barbiegirl42
- Post #8
- Forum: Introductory Physics Homework Help
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
Here is what my physics book says in two examples. As you can see, I used the examples as examples as to what I should do when I calculate the answer to this question. This is what I learned from the book and it made sense to me so I used some parts they did such as using the sin rule to...- barbiegirl42
- Post #7
- Forum: Introductory Physics Homework Help
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
why why would assume the angle to be 45 degrees? and where would I get this assumption from? and why are you dividing by the square root of 2 in the formula? I never learned that aspect in any calculations I did. Through all the examples in the book, the distance was always times by either the...- barbiegirl42
- Post #5
- Forum: Introductory Physics Homework Help
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
Well the Sin5 is the 5 degree angle to the horizontal and second 5 is the distance of 5m since the tightrope walker is 5m across thus you get the distance from the pivot point. Well I was thinking that the weight force would be half as in the adjacent side = F/2 and well the answer is 506 so...- barbiegirl42
- Post #3
- Forum: Introductory Physics Homework Help
-
B
Equilibrium Process for Calculating Tension in a Tight-Rope Walker's Wire
Homework Statement A 60 kg tight-rope walker carries a long beam with a mass of 30 kg across a 10 m long wire. When she is at the centre of the wire (i.e. 5 m across), each section of the wire makes an angle of 5° to the horizontal. Assuming that the mass of the wire is negligible, calculate...- barbiegirl42
- Thread
- Angles Equilibirium Equilibrium Forces Process Torque Wire
- Replies: 10
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
SO I managed to ask my physics teacher and he told me this: The high jumper’s energy at the top of his path is purely potential (as you have determined). When he hits the mat he is doing work on the mat to compress it. To do this work he must give up energy. His final energy when he finally...- barbiegirl42
- Post #27
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
Instead of arguing and asking me all these questions show me a equation that I can use and that will work and show me how it works, otherwise if I try to do the calculations using that equation and get something wrong and my answer turns out wrong then what am I supposed to do and you asking me...- barbiegirl42
- Post #23
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
Well if Ep at top=Ekat bottom Then the change in energy has to be 1356.81 There is no equation really just simple logic. I used Ep=mgh to find that value.- barbiegirl42
- Post #22
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
If you saw above on the 3rd post the guy gave me a hint to what equation to use to find the force: "But in order to get the given answer, you have to interpret it as the average over distance. This you would calculate as ∫F.ds/∫ds = ΔE/Δs, the change in energy divided by the displacement. This...- barbiegirl42
- Post #17
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
Still did not work. 1356.81/0.18 = 7537.83 - close but still not the answer.- barbiegirl42
- Post #15
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
As my previous post has, I pretty much did the same thing and got the same answer. I'm just getting more and more confused. You told me change in energy/displacement I did 1356.81/2.13 and got 637N, still the wrong answer.- barbiegirl42
- Post #13
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
I calculated the potential energy which is at the top of the jump. I know it becomes kinetic energy at the bottom (that's how I figured out the velocity) so I tried solving for force: W=Fs 1356.81=Fx2.13m F=1356.81/2.13 F= 637N ^ Wrong Answer- barbiegirl42
- Post #12
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
Yeah and I tried that equation and it seemed to not work and did not give the answer.- barbiegirl42
- Post #9
- Forum: Introductory Physics Homework Help
-
B
Average Net force and high jumpers
yeah but it asks for the mat and not the jumper and somehow i have to use the thickness and the compression of the mat to figure out the answer. I still am stuck on it and really all I need to help and for someone to explain how to do it- barbiegirl42
- Post #7
- Forum: Introductory Physics Homework Help