Recent content by barnikbhaumik

We know that the height attained by the ball is (v0²sin²ø)/2g<=H-h where H = the highest height attained and h is the height at which the ball is caught by the boys. Sin ø=√{(H-h)*2g/V0²} R= V0²/g*[2√{(H-h)*2g/v0²}][√{1-(H-h)*2g/V0²}]...simply to get the result