I took the second derivative and got:
g"(x)=-12x when x≤-2
g"(x)=12x when x>-2
because it's concave down when g"(x) is negative you only use the second part and then I get that g(x) is concave down on the open interval (-2,0)
I broke up g(x) into -2x^3+6x-4 when x≤-2 and 2x^3-6x+4 when x>-2 so the derivative when x≤-2 is -6x^2+6 and the derivative when x>-2 is 6x^2-6. I'm not sure if that's right though. I know g'(x) is undefined at -2.
I've already done the first part and the second part. I just need help on parts 3 and 4. How do I show that the g'(x) is undefined at -2? Can I do some sort of limit statement?
Extrema Problem - Need help
Please help me with this problem if you can:
The function f(x) is defined as f(x)=-2(x+2)(x-1)^2 on the open interval (-3,3).
1. Determine the coordinates of the relative extrema of f(x) in the open interval (-3,3)
2. Let g(x) be defined as g(x)= absolute...