Recent content by Bcisewski

Based on contraction and expansion due to heat and cold, have I assumed the correct answer with a sample equation to the question below. For the highest accuracy, would you choose an aluminum or a steel tape rule for year-round outdoor use? Why? “Aluminum” – The heat “Q” that must be...

I have a problem where one reading is 743mm at the top of the building and 760mm at the bottom of building. In order to find the height of the building I tried getting the difference of the two readings and multiply by the density of the mercury that it contains. I should come up with 179 m...

I could use some help on what formula or combination of formulas I am missing. An iron (p = 7860 kg/m3) cube measuring 15.4 cm on a side is suspended from a wire. Find the tension in the wire when the block is completely submerged in water (p = 1000 kg/m3). The answer is 246 N 1) I have...

Need some assistance on what I am missing "A tank contains mercury, whose density is 13 600 kg/m3. Find the force exerted by the mercury on a circular plug at the bottom of the tank. The plug has a diameter of 2.54 cm, and is located 37.6 cm below the surface of the mercury". The answer is...

Thanks for the assistance, I overlooked the cans as having space within. I guess sometime the obvious to some may be difficult to see for others.

Please correct me if wrong, but to explain why the mass of the pile is not pV = (2700 kg/m3)(1.0 m3) = 2700 kg, is because a pile of empty cans, its volume would be more of a dimension vs a weight. please explain concept if someone can. Thank you Question: A pile of empty aluminum cans has a...

Can anyone assist, I have tried various formulas on both problems with no luck. Thanks for any assistance or feedback. 1) A student (m = 59 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a time of 0.020 s. The average force...

Formula assistance, can anyone assist? A basketball player makes a jump shot. The 0.534-kg ball is released at a height of 2.01 m above the floor with a speed of 8.95 m/s. The ball goes through the net 3.48 m above the floor at a speed of 4.87 m/s. What is the work done on the ball by air...

1.95e7 is the same as 1.95x10^7?

Can someone help? It may seem elementary, but I have an application identifying a radius of 1.95e7m. What does the 1.95e7m convert to?

Can anyone provide some assistance? I know this comes in two parts, one in locating the velocity, which I believe comes down to v=sq root of 2(9.8)(6.34), however the second part is creating havoc. Any suggestions on part II's formula? A box slides down a frictionless 6.34 m high hill...