Recent content by bdeln

I've just been reading about how complex functions can be defined on the extended complex plane. They start with rational functions as examples, and defining them at oo so they're continuous at oo in a sense. Eg, 1/z would be defined to be 0 at z = oo. I understand that given a holomorphic...

Try dividing throughout by (1+e^t).

Well, we can check ... (t^3y)' = 3t^2y + t^3y', so other than the minus sign, I think you're good.

My first thought was the substitution u = xln(x), then du = (1 + ln(x)) dx, but the square root there messes it up.

Just pick the undifferentiated part from each term on the left hand side, ie, \left( e^{t^2} y \right)' = t^3 e^{t^2}

Hi opticaltempest, I believe the problem is that you're fixing z, then fixing x and y. The statement is, given some x and y, there exists z. If you fix all three, then it's easy to find a contradiction to the statement for all x,y, z, we have y - z = x, but this isn't what your original...

**bump** I'm working on a similar problem, ie, I need to find the period of 1/pq if (p,q) = (p,10) = (q,10) = 1. If the period of 1/p is r and the period of 1/q is s, then 10^r \equiv 1 (p) \mbox{ and } 10^s \equiv 1 (q). So, let t be the period of 1/pq, ie, 10^t \equiv 1 (pq), then 10^t...