Recent content by Beaker
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Prove that span ({x}) = {ax: a [tex]\in[/tex] F}
Is proving that W is a subspace necessary since a span(x) is the intersection of all subspaces containing x? But maybe I could show that span(x) is a subset of W and W is a subset of span(x) this would set them equal. Whoa, thanks you gave me allot to think about...back to the drawing board.- Beaker
- Post #3
- Forum: Calculus and Beyond Homework Help
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Prove that span ({x}) = {ax: a [tex]\in[/tex] F}
Homework Statement This is for any vector x in a vector space. The Attempt at a Solution span(x)={x1+x2+...+xn} x1=x2=...=xn x1+x2+...+xn=n*x=a*x a=n therefore ax is equal to span(x) There may be a few holes in my attempt. Sorry I posted this thread in the wrong forum twice.- Beaker
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- Span
- Replies: 4
- Forum: Calculus and Beyond Homework Help