Recent content by beep

Perfect. Thank you!

Ok, I gave it a shot. Can anyone tell me if this would be valid? * 0 < 1 , so 0 (+1) < 1 (+ 1 ) and 1 < 2 * If 2|1 then there exists an integer k such that 2 * k = 1 Case 1 * If k > 0, then 2*k ≥ 2 * 1 < 2 , thus 2*k > 1 * 2*k ≠ 1 , Thus 2 ∤ 1 Case 2 * If k = 0 then 2*k = 0 * 0 < 1...

No mention of even or odd Yes! I thought to try that first , but I was getting stuck. Partially because that comes with the next proposition I have to solve. Forgive me for being vague, this is my first proof based assignment for a class that started on Monday. Elementary Number Theor of N...

Prove 2 ∤ 1 , assuming the existence of the natural numbers and integers along with their most basic arithmetical and ordering properties. (Not allowed to use rational numbers) 2. Let and b be integers. We say a divides b if there exists an integer k such that ka = b. 3. Well, my...