Recent content by BenMcC

It's possible. It says to change the order of integration, and I have no idea how to set that up

I ended up working it out and got an answer of 8pi+1/2. Not entirely confident in that answer

What I tried with this problem: R:x≥0,y≥0 R≤4, so x^2+y^2≤4 -2≤x≤2, -sqrt(4-x^2)≤y≤sqrt(4-x^2) The integral looked like 2∏ ∫ ∫ (2+r^2)dr dθ 3∏/2 R My professor does not give good notes, so I can't really follow his examples

I typed the entire problem as it is on the assignment. There's nothing else with this problem

It only states that the radius, r=2. And since it's in the fourth quadrant, the limits of the angle would be just 3∏/2 to 2∏ I believe. But I have no idea how to set up this problem

I have 4 hours, so I have time. I'm just really confused how to do the initial integral. I tried u substitution of u*dv=uv-∫v*du, and I can't get it to come out quite right

I have this problem and I cannot even begin to start it. I have to hand it in today in a few hours, and I have been stuck on it for what seems like for ever. It reads: By using polar coordinates evaluate: ∫ ∫ (2+(x^2)+(y^2))dxdy R where R={x,y}:(x^2)+(y^2)≤4,x≥0,y≥0} Hint: The...

I have a problem with Double Integral that I can not seem to get correct. 4 2 ∫ ∫ e^(y^2)dydx 0 (x/2) The answer is (e^4)-1, but I can't seem to get the Substitution at all right. I have literally spent hours on this problem. Any help would be greatly appreciated, its...