Recent content by Bennyboymalon

Fantastic, I thought it was probably that and have got some answers. If you wanted to know; \mu = 0 and \lambda= 1 which i have then re-entered into the original definiton of F, and it does indeed return that the integral of F. dx is = 0. Thank you very much for your help! Much appreciated! :)

Thanks for your quick reply! I have calculated curl f and found it to be; (z-x(1+\mu)+2\mu)i + (-x-z+\muy)j + (x-z(1+2\mu)k which is = 0 for a conservative field. So how then can I solve this vector expression to get a value for \mu. Do i have to do the modulus of curl F and go from there...

We are told that the force field F=(\muz + y -x)i + (x-\lambdaz)j + (z+(\lambda-2)y - \mux)k Having already calculated in the previous parts of the question 1:the line integral (F.dx) along the straight line from (0,0,0) to (1,1,1) 2:the line integral (F.dx) along the path x(t)=(t,t,t^2)...